An elementary school is offering 3 language classes: one in spanish, one in french, and one in german. these classes are open to any of the 93 students in the school. there are 31 in the spanish class, 34 in the french class, and 23 in the german class. there are 12 students that in both spanish and french, 7 are in both spanish and german, and 9 are in both french and german. in addition, there are 3 students taking all 3 classes. if one student is chosen randomly, what is the probability that he or she is taking at least two language classes?

Hello! I would love to help!

In order to figure out the answer, we have to add up all the students that take 2 or more language classes, then divide it by the total number of students. Let's start!

Okay we know that:

12 in Spanish and French

7 Spanish and German

9 French and German

3 in All

Okay. Those are all the students that are taking 2 or more language classes. Now, let's add them all.

12+7+9+3=31

So 31 out of 93 kids take more than one language class. But, we still have to figure out the probability of choosing one of these kids randomly. Let's divide 31 and 93

31/93=0.333

I personally know 0.333 is equal to 1/3.

So, your answer for this question is 1/3!!

Hope this helped! Comment i you have any questions!

Iam guessing c. or d.

29. because you will divide each number of months by 12 to find the number of years. which would mean, 5, 12.5, 16, 45, 50, 72.5. which is crazy. anyhow, i think you find the median in the middle. and yea hope your test goes good