Let u=[1, c=[1,3, use the roster method to write the set c'.

The complement C' of some set C is essentially the set we get when we remove all of the elements of C from the universal set U.

Here, our universal set contains all of the numbers 1-16, and the set C contains all of the odd numbers between 1 and 16. If we were to put both of these sets in roster form:

If we remove all of the elements of C from the universal set U, we're left with the complement of C, which contains all of the even numbers between 1 and 16:

a is the correct

answer is because 4×10=40

and 98×4= is 392

40,392