Solve the given equation by using the quadratic formula. 2x2 - 3x - 4 = 0. what value is under the radical in your answer? (note: you are asked only to identify the value under the radical, not the solution to the equation.) 23 25 32 41

2x^2 - 3x - 4 = 0

x =  3 ± √ 41 / 4

The answer is 41 hope this helps.

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?