Acar leaves a town at 110 kilometers per hour. how long will it take a second car, travelling at 135 kilometers per hour, to catch the first car if it leaves 1 hour later?

Let t = travel time of the second car

then, (t+1) = travel time of the first car (since the first car starts start 1 hr before the second car)

When the second car catches the first car, they will have traveled the same distance

Write a distance equation: dist = speed * time

135*t = 110*(t+1)

135t = 110t + 110

25t = 110

t =110/25

t = 22/5 hours or 4.4 hours

Since 0.4 hours corresponds to 0.4*60 = 24 minutes, the total time is 4 hours and 24 minutes

So, the second car will catch the first car in 4 hours and 24 minutes

just do 5.2 + 2 ( 7.2) and 1/3 x 3 (.9) and youv'e got your equation. 0.9( 9/10) + 7.2 ^2 = 16.4 hope i could !

step-by-step explanation: