What is the value of the product (3 – 2i)(3 + 2i)?

The question follows the special product rule of polynomials.
(a-b)(a+b) = a^2 - b^2

From the given, (3-2i)(3+2i), then the answer will be 3^2 - (2i)^2
simplifying the
9 - 4i^2

Take note that i = square root of -1
Then, i^2 = -1

So, 9 - (4 * -1)
= 9 - -4
= 13.

So the answer is 13.