The length of a rectangle is 11 inches greater than twice the width. of the diagonal is 2 inches more than the length, find the dimensions of the rectangle

Width= W
length=2w+11
diagonal=2w+13
use the Pythagorean Theorem
(2w+13)^2=w^2+(2w+11)^2
4w^2+52w+169=w^2+4w^2+44w+121
simplify
52w+169=w^2+44w+121
w^2+44w-52w-169+121=0
w^2-8w-48=0
factor
(w-12)(w+4)=0
w-12=0
w=12 inches (width)
l=2*12+11=35 inches (length)

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