The length of a rectangle is 4 feet longer than twice the width of the same rectangle. if the perimiter of the rectangle is 68 feet, what are the dimensions of this rectangle?

Length (L): 2w + 4

width (w): w

Perimeter (P) = 2L + 2w

               68 = 2(2w + 4) + 2(w)

               68 = 4w + 8 + 2w

               68 = 6w + 8

               60 = 6w

               10 = w

Length (L): 2w + 4   = 2(10) + 4   = 20 + 4   = 24

width = 10 feet, length = 24 feet

6e14 is the answer.