Find the slope-intercept form of the lines with the following properties. parallel to the line y=3x-2 and passing through the point (1,4).

Hello!

If you want to find an equation that is parallel to another equation, and passing through the point (1, 4), you need to create a new equation with the same slope, you need to substitute the given point into the new equation to find the y-intercept.

m = 3, y = 3x + b (substitute the ordered pair)

4 = 3(1) + b (simplify)

4 = 3 + b (subtract 3 from both sides)

b = 1

Therefore, the line parallel to the line y = 3x - 2 and passing through the point (1, 4) is y = 3x + 1.

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.

a and c

step-by-step explanation: