Can you me to write this math problem?

Step 1: Flip the equation.

x−2=y

Step 2: Add 2 to both sides.

x−2+2=y+2

x=y+2

x=y+2

If solving for Y then

y=x−2

-x + y + 2 = 0

(-1) *x + (y+2) = 0

x = -(x+2)/-1

x = y + 2

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180

16 is the absolute value

step-by-step explanation: