The length of a rectangle is 6 inches longer than it’s width what are the possible widths if the area of the rectangle is at least 667 in.²

Let the width = x

length = x + 6

(x + 6) * x = 667

Simplify

x² + 6 = 667

x² + 6 (-6) = 667 (-6)

x² = 661

√x² = √661

x = √661

x = 25.71 (rounded)

25.71 in. is your width

hope this helps

this linear equation would have just one solution.

step-by-step explanation:

the reason why this would have one solution is that it is an expression with just one variable. since that variable is not raised to a power, it will always have just one solution.