If a boy grows 5 inches, he will be one-half as tall as his sister. his sister is 68 inches tall. how tall is the boy?

If the boy grows another 5 inches, he will be 1/2 as tall as his sister. HIs sister is 68 inch tall

Let sister = g, and boy = b

2b + 5 = g

g = 68

Plug in 68 for g

2b + 5 = 68

Isolate the b. Note the equal sign. What you do to one side, you do to the other. Do the opposite of PEMDAS.

first, subtract 5 from both sdies

2b + 5 (-5) = 68 (-5)

2b = 68 - 5

2b = 63

Isolate the b. Divide 2 from both sides

2b/2 = 63/2

b = 63/2

b = 31.5

The boy is 31.5 inches tall

hope this helps

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.