2.5= 7.9 - 6x 16=9x + 1 - 4x 5(7x - 2) = 60 n/4 - 7n/8 = 1/4 can yall me ?

Solve for x:

2.5 = 7.9 - 6 x

2.5 = 7.9 - 6 x is equivalent to 7.9 - 6 x = 2.5:

7.9 - 6 x = 2.5

Subtract 7.9` from both sides:

(7.9 - 7.9) - 6 x = 2.5 - 7.9

7.9 - 7.9 = 0:

-6 x = 2.5 - 7.9

2.5 - 7.9 = -5.4:

-6 x = -5.4

Divide both sides of -6 x = -5.4 by -6:

(-6 x)/(-6) = (-5.4)/(-6)

(-6)/(-6) = 1:

x = (-5.4)/(-6)

(-5.4)/(-6) = 0.9:

 x = 0.9

Grouping like terms, 9 x - 4 x + 1 = (9 x - 4 x) + 1:

16 = (9 x - 4 x) + 1

9 x - 4 x = 5 x:

16 = 5 x + 1

16 = 5 x + 1 is equivalent to 5 x + 1 = 16:

5 x + 1 = 16

Subtract 1 from both sides:

5 x + (1 - 1) = 16 - 1

1 - 1 = 0:

5 x = 16 - 1

16 - 1 = 15:

5 x = 15

Divide both sides of 5 x = 15 by 5:

(5 x)/5 = 15/5

5/5 = 1:

x = 15/5

The gcd of 15 and 5 is 5, so 15/5 = (5×3)/(5×1) = 5/5×3 = 3:

 x = 3

Solve for x:

5 (7 x - 2) = 60

Divide both sides of 5 (7 x - 2) = 60 by 5:

(5 (7 x - 2))/5 = 60/5

5/5 = 1:

7 x - 2 = 60/5

The gcd of 60 and 5 is 5, so 60/5 = (5×12)/(5×1) = 5/5×12 = 12:

7 x - 2 = 12

Add 2 to both sides:

7 x + (2 - 2) = 2 + 12

2 - 2 = 0:

7 x = 12 + 2

12 + 2 = 14:

7 x = 14

Divide both sides of 7 x = 14 by 7:

(7 x)/7 = 14/7

7/7 = 1:

x = 14/7

The gcd of 14 and 7 is 7, so 14/7 = (7×2)/(7×1) = 7/7×2 = 2:

 x = 2

Solve for n:

n/4 - (7 n)/8 = 1/4

Put each term in n/4 - (7 n)/8 over the common denominator 8: n/4 - (7 n)/8 = (2 n)/8 - (7 n)/8:

(2 n)/8 - (7 n)/8 = 1/4

(2 n)/8 - (7 n)/8 = (2 n - 7 n)/8:

(2 n - 7 n)/8 = 1/4

2 n - 7 n = -5 n:

(-5 n)/8 = 1/4

Multiply both sides of (-5 n)/8 = 1/4 by -8/5:

(-8 (-5) n)/(5×8) = ((-8)/5)/4

((-8)/5)/4 = (-8)/(5×4):

(-8 (-5) n)/(5×8) = (-8)/(5×4)

(-8)/8 = (8 (-1))/8 = -1:

(-5-1 n)/5 = (-8)/(5×4)

(-5)/5 = (5 (-1))/5 = -1:

--1 n = (-8)/(5×4)

(-1)^2 = 1:

n = (-8)/(5×4)

(-8)/4 = (4 (-2))/4 = -2:

 n = (-2)/5

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

i dont know men

step-by-step explanation: