Jack uses a probability simulator to roll a six-sided number cube 100 times and to flip a coin 100 times. the results of the experiment are shown below: number on the cube number of times rolled 1 16 2 14 3 5 4 17 5 21 6 27 heads tails 41 59 using jack's simulation, what is the probability of rolling a 6 on the number cube and the coin landing on heads? fraction 1,107 over 10,000 fraction 1,593 over 10,000 fraction 27 over 100 fraction 41 over 100

The experimental probability is the number of specific outcomes divided by the sample size...

P(6)=27/100  (27%)

P(H)=41/100  (41%)

Not sure, but if you meant rolling a 6 AND getting a head then:

P(6 AND H)=(27/100)(41/100)=1107/10000  (11.07%)

The probability of rolling a 6 on the number cube and the coin landing on heads is:

            fraction 1,107 over 10,000 i.e.        

Let A denote the event of rolling a 6 on number cube.

and B denote the event of landing a head on a coin.

Clearly both the events A and B are independent.

Also, let P denote the probability of an event.

We are asked to find: P(A∩B)

We know that when two events A and B are independent.

Then,

Now, based on the two tables we have:

( Since, 6 comes up on rolling a number cube 27 times out of a total of 100 times)

Also,

( since head comes up 41 times out of a total of 100 times)

Hence, we get:

i.e.

i.e.

step-by-step explanation:

i could only see the first page. the other pages were blurry. ; -;

x hot dogs for 2$, y drinks for 3$. 29 items and total 70

2x+3y=70

x+y=29

if x=17and y=12

2(17)+3(12)=70

34+36=70

can you add an image ?

step-by-step explanation: