Find the equation of a circle passing through two points with a radius of 4

Circle formula:  (x - h)² + (y - k)² = r²   ; where (h,k) is the vertex & "r" is the radius

Since the radius is 4,    (x - h)² + (y - k)² = 4²   →   (x - h)² + (y - k)² = 16

1) If you have two points, replace "x" and "y" with the coordinates to create two equations with unknown variables "h" and "k".  

2) Then solve the system to determine the value of "h" and "k".

3) Input the values of "h", "k", and "r" into the Circle Formula.

it would more likely be bald eagle because its has more in the box so about 75%.

step-by-step explanation:

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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