Find three consecutive integers whose products is 85 larger than the cube of the smallest integer

Let the numbers be x, x + 1 and x + 2.

From the information given:-

x(x + 1)(x + 2) = x^3 + 85    

Solving for x:-

x(x^2 + 3x + 2) = x^3 + 85

x^3 + 3x^2 + 2x = x^3 + 85

3x^2 + 2x - 85 = 0

3x^2 - 15x + 17x - 85 = 0

3x(x - 5) + 17(x - 5) = 0

(3x + 17)(x - 5) = 0

x = -17/3 ,  5

We take x = 5 because x is an integer.

- the 3 integers  are  5, 6 and 7.

536

step-by-step explanation:

answer: a. 13/44

step-by-step explanation: judging by the information given to us, we are looking for experimental probability. we can see that 13 males have chosen chocolate ice cream. there are 44 ice creams in total (remember that the total is always the denominator). so our answer is 13/44.