Acarpenter purchased 50 ft of redwood and 80 ft of pine for a total cost of $285. a second purchase, at the same prices, included 80 ft of redwood and 50 ft of pine for a total cost of $339. find the cost per foot of redwood and of pine.

Hey there!!

Let us take the price of the redwood as ' x ' and pine as ' y '

Then , we take it into an equation. We get,

50x + 80y = 285 ( 1 )

80x + 50y = 339 ( 2 )

Now, multiply the first equation with 8 and the second equation with 5

400x + 640y = 2280

400x + 250y = 1695

Now subtract the second equation from the first

390y = 585

y = 585 / 390

y = $1.5

Now substitute this into any equation

50x + ( 80 ) ( 1.5 ) = 285

50x + 120 = 285

50x = 165

x = 165 / 50

x = $3.3

Redwood = $3.3

Pine = $1.5

Hope helps!

Let R = cost per foot of redwood, and

let P = cost per foot of pine.

The 1st sentence gives us 60 ft * R + 90 ft * P = $303, and

the 2nd sentence gives us 90 ft * R + 60 ft * P = $357.

So this is two equations and two unknowns, so we should be able to solve these.

Solve the first equation for P: 60 ft * R + 90 ft * P = $303

Subtract 60 ft * R from both sides of the equation: 90 ft * P = $303 - 60 ft * R

Now divide both sides of the equation by 90 ft: P = ($303 - 60 ft * R) / 90 ft = $101 / 30 ft - 2/3 * R

Next, substitute P into the second equation: 90 ft * R + 60 ft * P = $357

so we then have 90 ft * R + 60 ft * [$101 / 30 ft - 2/3 * R] = $357.

Now solve for R (remember, parentheses, exponents, multiplication and division, addition and subtraction):

90 ft * R + [$202 - 40 ft * R] = 50 ft * R + $202 = $357, or 50 ft * R = $155; so R = $155 / 50 ft = $3.10 / ft.

Now we can substitute this value for R into the first equation and solve for P: 60 ft * R + 90 ft * P = $303

so we then have 60 ft * $3.10 / ft + 90 ft * P = $303, or $186 + 90 ft * P = $303.

Subtracting $186 from both sides of the equation, and then dividing by 90 ft, we have P = $1.30 / ft

So P = $1.30/ft, and R = $3.10/ft.

To check this answer, plug both into the second equation:

90 ft * R + 60 ft * P = $357

90 ft * $3.10/ft + 60 ft * $1.30/ft = $279 + $78 = $357

3.how is solving radical equations different than solving linear equations?

step-by-step explanation: