In one day, 125,683 people fly in and out of an airport in texas. how many thousands of people fly in and out that day?

125 thousands of people flew out that day.

125 thousands of people fly in and out that day.              

Step-by-step explanation:

Given : In one day, 125,683 people fly in and out of an airport in Texas.

To find : How many thousands of people fly in and out that day?

Solution :

According to place value system,

Hundred Th.   Ten Th.   Thousand   Hundred    Tens    Ones

       1                    2                5                6              8           3

There are 125 thousands 6 hundred and 83.

In one day, 125,683 people fly in and out of an airport in Texas.

Number of thousands of people fly in and out that day is 125.

Therefore, 125 thousands of people fly in and out that day.

step-by-step explanation:

equation

you are asked to write the equation

  expression = 0

using the given expression. when you do that, you have

  2x^2-2x-12 = 0

factoring

you can see that each of the coefficients is even, so a factor of 2 can be removed immediately.

  2(x^2 -x -6) = 0

if you multiply the binomials (x+a)(x+b), you get

  (x +a)(x +b) = x^2 +(a+b)x +ab

this tells you the coefficient of x is the sum of two factors of the constant term. here, that means -1 is the sum of two factors of -6. we want to know those factors so we can factor the trinomial.

  -6 = -1×6 = -2×3 = -3×2 = -6×1

the factor pair that sums to -1 is {-3, 2}, so our factorization is

  2(x -3)(x +2) = 0

solutions

the solutions to this equation are the values of x that make the product zero. a product is zero only when only of the factors of the product is zero. here, that means

  x - 3 = 0

  x = 3 . . . add 3 to both sides of the equation

or

  x +2 = 0

  x = -2 . . . add -2 to both sides of the equation

the solutions to the equation are x=3 or x=-2. both of these values of x satisfy the equation—they make it be true.

step-by-step explanation: