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![\bf ~~~~~~\textit{parabola vertex form} \\\\ y=a(x- h)^2+ k~\hspace{7em}vertex~~(\stackrel{}{ h},\stackrel{}{ k}) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \stackrel{f(x)}{y}=(x+1)^2-8\implies y=1[x-(\stackrel{h}{-1})]^2+(\stackrel{k}{-8})~\hfill \stackrel{vertex}{(-1,-8)}](/tpl/images/0074/8533/cf748.png)
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F(x)=(x+1)^2-8 give axis of symmetry and vertex...
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