Abaseball player hit 62 home runs in a season. of the 62 home runs, 24 went to right field, 17 went to right center field, 9 went to center field, 10 went to left center field, and 2 went to left field. (a) what is the probability that a randomly selected home run was hit to right field? (b) what is the probability that a randomly selected home run was hit to left field? (c) was it unusual for this player to hit a home run to left field? explain.

Explanation

Total home runs = 62

Right field = 24 ,  Right center field = 17,  Center field = 9 ,  Left center field = 10 and Left field = 2

(a) The probability that a randomly selected home run was hit to right field            = (Number of right field / Total home runs) =

(b) The probability that a randomly selected home run was hit to left field       =  (Number of left field / Total home runs) =

(c)  As the probability that a home run was hit to the left field is 0.0322... or 3.22...% , that means there is very low chance for hitting to the left field. So, it was unusual for this player to hit a home run to left field.

20

step-by-step explanation:

you didn't post any answer choices, so its not 100% clear what your teacher is looking for

however, log(15/7) is equivalent to log(15) - log(7)

i'm using the rule log(x/y) = log(x) - log(y)