Twice a number increased by 3 is less than the number decreased by 4

Set it up like this: 2n+3 < n-4

Solve for n:

2n+3 < n-4

-n        -n                (1st step: get n on one side by itself)

n+3 < -4

  -3   -3                (2nd step: subtract 3 from both sides)

n < -7

The answer is n < -7

10 miles

step-by-step explanation:

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

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