Suppose you purchase a car for $24,500, and it depreciates at the rate of $1500 a year. express the car's value after five years as a term in an arithmetic sequence.

The arithmetic sequence is

24,500,23,000, 21,500,20,000,18,500,17,000

The car's value after five years is $17,000

Step-by-step explanation:

Let

n > the number of years

a(n) > the car's value

we know that

The arithmetic sequence that represent this situation is

a(n)=-1,500n+24,500

where

-1,500 is the common difference

so

For n=0 (initial value)

a(0)=-1,500(0)+24,500=24,500

For n=1 (First year)

a(1)=-1,500(1)+24,500=23,000

For n=2 (Second year)

a(2)=-1,500(2)+24,500=21.500

For n=3 (Third year)

a(3)=-1,500(3)+24,500=20,000

For n=4 (Fourth year)

a(4)=-1,500(4)+24,500=18,500

For n=5 (Fifth year)

a(5)=-1,500(5)+24,500=17,000

The arithmetic sequence is

24,500,23,000, 21,500,20,000,18,500,17,000

that there are 12 data points

step-by-step explanation:

step-by-step explanation: s