What is the sound level for a noise that has an intensity of 9.9 × 10-5 watts/m2?

Given: Sound Intensity ( I ) =

We know,  the approximate threshold of human hearing is at 1kHz. In watts/m^2 it's value is ⁻¹² W/m².

So, we can say,  Reference sound intensity = 10⁻¹² W/m².

We have formula for "sound intensity level LI in dB" when entering sound intensity.

LI = 10×log (I / Io)  in dB

Plugging values of I and Io in formula.

LI = 10 × log ()

LI = 10 × log (99000000)

= 10 × 7.99564

LI = 79.96 dB.

Therefore,  79.96 dB is the sound level for a noise that has an intensity of 9.9 × 10-5 watts/m2.

the answer will be

a; x = 0.5

step-by-step explanation:

-10x = -5

x = 0.5