Find largest three consecutive even integers with a sum is at most 126

let's say our first integer is say 2a, bearing in mind that 2 times any number, gives us an even value, regardless of what that "a" number might be.

let's notice something, 2, 4, 6, 8, 10......, to get a consecutive even number, we simply hop twice either forwards or backwards, namely 6±2 gives us 4 and 8, and both are even, so let's move forwards and use 2a + 2 for the second one.

so if the first integer is 2a, the next consecutive is 2a + 2, and the third integer will be 2a + 4.

we know they all add up to 126, so

b is the answer that makes most sense

step-by-step explanation:

maybe i can