Zachary can spend no more than $98 per day to rent a car. a car rents for $35 per day plus $0.21 per mile. what is the maximum number of miles that he can drive the car?

The maximum number of miles that he can drive the car will be 300 miles.

Explanation

Suppose, the number of miles he can drive the car is

The car rents for $35 per day plus $0.21 per mile. So, the total cost for miles

As he can spend no more than $98 per day, so.....

Thus, the maximum number of miles that he can drive the car will be 300 miles.

true !

step-by-step explanation:

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)