Given the rectangle abcd shown below has a total area of 72. e is in the midpoint of bc and f is the midpoint of dc. what is the area of the inscribed triangle aef.

Refer to the attached image.

Given the rectangle ABCD of length 'l' and height 'h'.

Therefore, CD=AB = 'l' and BC = AD = 'h'

We have to determine the area of triangle AEF.

Area of triangle AEF = Area of rectangle ABCD - Area of triangle ADF - Area of triangle ECF - Area of triangle ABE

Area of triangle ADF =

=

=

Area of triangle ECF =

=

=

Area of triangle ABE =

=

=

Now, area of triangle AEF =

Area of rectangle ABCD - Area of triangle ADF - Area of triangle ECF - Area of triangle ABE

=

=

=

=

= 27 units

Therefore, the area of triangle AEF is 27 units.

this answer is !