What is the interquartile range for the following data set?
(5,6,7,3,9,8,3,1,6,7,7)

Step-by-step explanation:

We have been given a data set and we are asked to find the Interquartile Range for our given data set.

Since we know that IQR is the difference between upper quartile and lower quartile, so we need to find for our given data set.

First of all let arrange data points of our given data set in ascending order.

1, 3, 3, 5, 6, 6, 7, 7, 7, 8, 9.

, where n represents total number of data points.

Since 3rd data point of our given data set is 3, so lower quartile of our data set is 3.

, where n represents total number of data points.

Since 9th data point of our given data set is 7, so upper quartile of our data set is 7.

Therefore,interquartile range for our given data set is 4.

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;