Aship sails 20km due north and then 35km due east .how far east is it from its starting point?

Use the Pythagoras' Theorem:

A^2 + B^2 = C^2

20^2 + 35^2 = C^2

400+ 1225=1625=C^2

square root of 1625= C = 40.31 km

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x -

median = 1.25

range = 12-14.5

interquartile = q12-q14.5

y -

median = 1

range = 15-17

interquartile = q15-q17

to find the perimeter of the rectangle this is the expression:

x-9+x-9+3x-4+3x-4=138

if we simplify it:

8x-26=138

remember, 138 is what it all adds up to

the length is 11.5cm

the width is 57.5cm

the area is 661.25cm^2

the answers might not be correct use at own risk