Find a vector equation for the line through the point p = (5, 0, 0) and parallel to the vector v = (5, 3, -1). assume ]and that v is the velocity vector of the line..

Answer- r(t) = (5,0,0) + t(5,3,-1)

Solution - we have been given the point vector P as (5,0,0) and the velocity vector V as (5,3,-1)

The general form for the vector equation of a line is (x,y,z) =         \

(Px, Py, Pz) + t(Vx, Vy, Vz)

Where P is a point, V is a vector and t is a scalar parameter.

Therefore, the vector equation of the requested line is:  

r(t) = r(x,y,z) =  (5,0,0) + t(5,3,-1)

been looking for the answer havent been able to find it   but good luck with it

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3