Aflying squirrel lives in a nest that is 6 meters up in a tree, but wants to eat an acorn that is on the ground 4 meters away from the base of her tree. if the flying squirrel glides from her nest to the acorn, then scurries back to the base of the tree, and then climbs back up the tree to her nest, how far will the flying squirrel travel in total? if necessary, round to the nearest tenth.

i belive it flew 20 meters in total

he has now walked a total of what?

if i know what this is maybe i can

step-by-step explanation:

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form