Find the vector represented by the directed line segment with initial point a(2, −4, 1) and terminal point b(−1, 1, 4).

A(2, −4, 1) and terminal point B(−1, 1, 4).

Vector AB = B-A

=(−1, 1, 4)  - (2, −4, 1)

=(−1-2, 1- -4, 4-1)

= (−3, 5, 3)

3< x< 5

step-by-step explanation:

|x - 4| < 1

there are two solutions, one positive and one negative.   remember to flip the inequality when taking the negative solution

x-4 < 1       x-4 > -1

add 4 to each side

x-4+4 < 1+4       x-4+4 > -1+4

x< 5                 x> 3

3< x< 5

the answer is d

step-by-step explanation:

y+3=-4(x-2)

y+3=-4x+8

  -3         -3  

y=-4x+5