What is the nth term of -4,-3,0,5,12,21,32?

The first set of differences is   1,3,5,7,9,11

second set of difference = 2 so this is a quadratic sequence  with first term n^2

subtract n^2 from the sequence:-

-4  -  3    0     5

1      4     9    16

-5   -7    -9     -11  

This last series is an AP with nth term = - 5-2(n - 1)

so nth term  for original series is n^2 - 5 - 2(n - 1)

= n^2  - 2n  - 3  answer

sorry i got nothing

step-by-step explanation:

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