If synthetic division reveals a zero, why should we try that value again as a possible solution? - polynomial functions can have imaginary zeros, so if it is an imaginary zero, it could also be a real zero. - polynomial functions can have repeated zeros, so the fact that a number is a zero doesn't preclude it being a zero again. - polynomial functions can have real zeros, so the fact that a number is a real zero means it could also be an imaginary zero. - polynomial functions can have imaginary zeros, so if it is a zero, it could also be an imaginary zero. - polynomial functions can have rational zeros, so trying a value again can find irrational zeros.

The correct option is:

Polynomial functions can have repeated zeros, so the fact that a number is a zero doesn't preclude it being a zero again.

Step-by-step explanation:

As we know that if we get a zero of a polynomial than that particular zero could also be a zero of multiplicity greater than one or in short we can say that it is a repeated zero of the polynomial.

Hence, in order to check that it is a repeated zero we factorize the polynomial and see that it is a zero of the other factor or not if it is a zero of the other factor then we will say that the zero is a repeated zero of the polynomial.

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions

what do u need to know

step-by-step explanation: