Rita will rent a car for the weekend. she can choose one of two plans. the first plan has no initial fee but costs $0.90 per mile driven. the second plan has an initial fee of $60 and costs an additional $0.40 per mile driven. how many miles would rita need to drive for the two plans to cost the same?

Let M = #miles driven

Plan 1:   .50M + 70  = total cost

Plan 2    .70M = total cost

To know how far she would drive to have an equal cost for either plan just set the equations equal to each other

.70M = .50M + 70

subtract .50M from both sides

.20M = 70

M = 70/.20 = 350 miles

Check the answser:

Plan 1:  .50(350) + 70 = 175 + 70 = $245

Plan 2:  .7(350) = $245

they are equal so our answer checks as correct

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b

for a it would be 24 children.

for b i don't understand the question. is it saying for each individual person they pick 5 reds to 7 greens or is it the whole group. clarify and i hope this can you.

step-by-step explanation: