What value of x is in the solution set of 3(x – 4) ≥ 5x + 2? –10 –5 5 10

First, distribute 3 to all terms within the parenthesis

3(x - 4) = 3x - 12

3x - 12 ≥ 5x + 2

Isolate the x. Subtract 5x from both sides, and add 12 to both sides

3x (-5x) - 12 (+12) ≥ 5x(-5x) + 2 (+ 12)

3x - 5x ≥ 2 + 12

Simplify

-2x ≥ 14

Isolate the x. Divide -2 from both sides. Note that when dividing a negative number, you must flip the sign.

-2x/-2 ≥ 14/-2

x ≥ 14/-2

x ≤ -7

x ≤ -7 is your expression. Any number equal too, or less than -7 is your answer

–10 is your answer

hope this helps

the answer is -10 that's the right answer

360/29

step-by-step explanation: