Will give brainliest to who is correct solve for x over the complex numbers. x^2+10x+41=0 x = or x=

x²+10x+41=0

using x=(-b±√b²-4ac)½

where a= 1

b=10

c=41

x= (-10±√10²-4×1×41)½

x=-5 ± √(100-164)

x=-5±√(-64)½

x=-5±4i

x=-5+4i or -5-4i  

where i= √-1

ANSWER: x=-5+4i or -5-4i  

i believe the answer is letter c) 8

step-by-step explanation: