Determine what value(s) for the variable would make each algebraic equation a true number sentence. 6p=3p+2p+p6p=3p+2p+p

We are given equation 6p=3p+2p+p.

Let us simplify right side of the eqaution by combing all like terms.

We have 3p+2p+p on rigth side.

We don't have any number in front of left term p.

p could be written as 1p.

So, 3p+2p+p could be written as 3p+2p+1p.

Now, we can add like terms

On adding 3p+2p+1p, we get 6p.

Substituting this value in original equation, we get

6p=6p.

We got both sides same.

When we get same terms on both sides of an equation, the equation would have solution as " All real numbers".

Because we can take any value for unknown variable p.

On plugging any value of p, it would give left side equal to rigth side.

Therefore, we can say "All real number for the variable would make each algebraic equation a true number sentence.:"

the answer is a

step-by-step explanation:

39.00 x 24 = total installment price

carrying installment price - cash price

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