Consider the curve y = x − x^3, find the slope of the tangent line to the curve at the point (1, 0).

The derivative of a function, such as the one given above, represents the slope of the tangent line to the curve at the given point.

In this case, y = x − x^3, and dy/dx = 1 - 3x^2.  Letting x = 1, we get the slope of the tangent line at the point (1,0):  1 - 3(1^2) = -2 (answer)

this is not an educational question, do not offer numerous points just for your own entertainment

i think it's ф or x=6,-6

step-by-step explanation:

-x^2=-36

x^2=-36

ф

or

if you mean by : -(x^2)=-36

it'll be: x^2=36

x=6,x=-6

hope it'll ! have a good day!

you for asking!