The area of the rhombus is 540 cm2; the length of one of its diagonals is 4.5 dm. what is the distance between the point of intersection of the diagonals and the side of the rhombus?

Area of rhombus =

where x and y are diagonals.

Given length of one diagonal is 4.5 dm

So, let x= 4.5dm

1 dm = 10 cm

4.5dm= 45cm

area =

so,

y = 24 cm

The two diagonals are x= 45cm and y = 24cm

Since diagonals bisect each other, we get 22.5cm and 12cm

Using right triangle formula

r = 10.588cm

Distance of center to the side =  = 5.294 cm

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option

a is the right answer