Ms. meyer remarks, "isn't it great? this theater usually charges $9 per student. on student night, i can bring 47 more students for the same cost! " how many students can ms. meyer bring to the theater? tickets: $6

Let's assume

Ms.Meyer used to bring x students for the cost $9 per student

so, total cost = 9x

now, we are given

For ticket cost $6 , she can brings 47 more students

so, total students =x+47

total cost =6*(x+47)

now, we are given total costs are same for both

we get

we can solve for x

Subtract both sides by 6x

Divide both sides by 3

so, Ms. Meyer brings 94 students to theatre.........Answer

i do not know this sorry : (

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15