The midpoint of  is point p at (−6,−2). if point e is at (2,−4), what are the coordinates of point f? (−14,0)(−10,−8)(−5,3)(−2,−3)

F would be (-14, 0)

In order to find this, we first have to note that the coordinates of P would simply be the average of it's E and F counterparts. We'll first start by finding the x value.

(Ex + Fx)/2 = Px

(2 + Fx)/2 = -6

2 + Fx = -12

Fx = -14

Now we'll do the same for the y coordinate.

(Ey + Fy)/2 = Py

(-4 + Fy)/2 = -2

-4 + Fy = -4

Fy = 0

answer: standard form is ax^2 + bx + c = 0

step-by-step explanation:

standard form is ax^2 + bx + c = 0

(2x + 1)(x - 2) = 0

distribute to get into standard form

2x^2 - 4x + x - 2 = 0

2x^2 - 3x - 2 = 0

a = 2, b= -3, c = -2

a is your answer

step-by-step :