Given that f(x) = 6x2 + 72, find x.

Values of x are:

±2i√3

We have to find x in f(x)=6x²+72

i.e. those values of x for which

6x²+72=0

Subtracting 72 from both sides, we get

6x² = -72

Dividing both sides by 6, we get

x² = -12

Taking square root on both sides, we get

x = ±2i√3

Hence, Values of x are:

±2i√3

3 1/3 x 2 3/5 = 8 2/3

step-by-step explanation:

just multiply the first number by the second number to get your answer.