Asher is asked to find the factors of 10. his work is below. 10 x 1 10 10 x 2 20 10 x 3 30 so, the factors of 10 are 10, 20, and 30 which statements are true of asher's work and his answer? check all that apply o asher made errors in multiplication. o asher found multiples of 10, not factors of 10. o asher should have multiplied 10 x 4 as well. o asher should have gotten this as the 1,2,5, and 10 o asher should have gotten this as the 10, 20, 30 40,

Asher did 10 x 1= 10, 10 x 2= 20, 10 x 3= 30

In Asher's work, each 10 is being multiplied with 1,2,3.

Multiplication represents multiples of a number.

In order to find the factors of a number, we need to find all numbers that can divide that particular number we need to find factor for.

Therefore, to find the factors of 10, we need to find the numbers that can divide 10 completely.

We can start from 1.

10 can be divided by 1. So, first factor of 10 is 1.

Now, if we check 2, we can see that 2 can also divide 10 completely.

Now checking 3,4. Those numbers can't divide 10 completely.

Now checking 5. 5 can also be divide 10 completely.

And next number is 10, that can divide 10 completely.

Therefore, factors of 10 are 1,2,5 and 10.

So, the following statements are applicable:

B) Asher found multiples of 10, not factors of 10.

D) Asher should have gotten this as the 1,2,5, and 10

you didn't give me the choices, so i will just give you the graph so you can look at your choices and choose the right one.

answer: c, the green line

step-by-step explanation:

there is no black line, eliminate b.

simple interest implies periodic payments, but the red line shows no payments, eliminate d.

simple interest has equal payments. if paid say every day, the graph is about a straight line (actually a stairstep).

the yellow line is not straight, eliminate a.

check: the green line is straight, answer is c.

simple interest with positive interest rate gives a straight line sloping up to the right. green line:

g(t) = $100 + ($200-$100) ÷ (20 years) × (t years)

= $100 + (4%/year) × ($100)(t years)

incidentally, the yellow line curving upward represents continuously compounded interest

y = $100 × 2^(t years / (14 assuming the yellow line hits $200 at 14 years. 2^0 is 1, so y(0) = $100; 2^(14/14) is 2, so y(14) = $200.