At a particular school with 200 male students, 58 play football, 40 play basketball, and 8 play both. what is the probability that a randomly selected male student plays neither sport?

Step-by-step explanation:

Total male students = 200

Students who play football (F)= 58

Students who play basketball (B)= 40

Students who play both (F∩B)= 8

The number of students who play either sport is

The number of students who play neither sport is

The probability that a randomly selected male student plays neither sport is

Hence, the required probability is .

6, 10

9, -13

12, -21

18, -23

step-by-step explanation:

you just add 6 to the x-coordinate and subtract 10 from the y-coordinate.

i believe the answer is 68cm

step-by-step explanation:

i just took 34 x 2 because the space between v and y is the same as y to k.