Find three consecutive even integers such that three times the smallest is four more than twice the largest

n, n + 2, n + 4 - three consecutive even integers

3n = 2(n + 4) + 4     |use distributive property

3n = (2)(n) + (2)(4) + 4

3n = 2n + 8 + 4

3n = 2n + 12    |subtract 2n from both sides

n = 12

n + 2 = 12 + 2 = 14

n + 4 = 12 + 4 = 16

12, 14, 16.

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