Suppose you just received a shipment of eleven televisions. two of the televisions are defective. if two televisions are randomly selected, compute the probability that both televisions work. what is the probability at least one of the two televisions does not work?

Explanation:

Since the total number of television= 11

Number of defective television = 2

Remaining  television that are working = 9

Now,

∴

The probability at least one of the two televisions does not work is 0.345

Given the following parameters:

total  number of television shipped = 11

Defective television = 2

Non defective = 11 - 2 = 9

Pr(two television does not work) =

Similarly;

The probability at least one of the two televisions does not work =

The probability at least one of the two televisions does not work =

Hence the probability at least one of the two televisions does not work is 0.345

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the height of the surface increases from the center out to the sides of the road

it is c!

this is a direct variation proportion. y = kx

y is the total amount due, k is the constant of variation, and x is the number of texts sent.

plug in the 3.20 and the 16 to solve for the "k". this is the constant of proportionality. it is the value that will not change.

3.20 = k(16). solving you get $.20 per text.

the equation would then be y = .20x