Write an equation for a line parallel to y=3x-3 and passing through the point (4,15)

Hello!

To find the equation of a line parallel to y = 3x - 3 and passing through the point (4, 15), we need to know that if two lines are parallel, then their slopes are equivalent.

This means that we create a new equation in slope-intercept form, which includes the original slope, which is equal to 3.

In slope-intercept form, we need a y-intercept. So, we would substitute the given ordered pair into the new equation with the same slope and solve.

Remember that slope-intercept form is: y = mx + b, where m is the slope and b is the y-intercept.

y = 3x + b (substitute the ordered pair (4, 15))

15 = 3(4) + b (simplify)

15 = 12 + b (subtract 12 from both sides)

3 = b

Therefore, the equation for the line parallel to the line y = 3x - 3, and passing through the point (4, 15) is y = 3x + 3.

y + 11 = (1/4)(x + 16)

step-by-step explanation: