When the length of a rectangle is x inches and the width is y inches, the perimeter is 30 inches. if the length is tripled and the width is quadrupled the perimeter becomes 102 inches. find the length and width of the original rectangle

P1=2x+2y=30

after modify them

P2=2*3x+2*4y=102

     6x+8y=102

      2x+2y=30      / * (-3)

      -6x-6y= -90

       6x+8y=102

we must add the 2 expressions

         / 8y-6y=102-90

            2y=12

           y=12:2

          y=6

       2*x+2*y=30

       2x+2*6=30

       2x+12=30

      2x=30-12

     2x=18

      x=18:2

      x=9

bn,mn,n.vn.

step-by-step explanation:

answer 1 : option "c"

answer 2 : option "d"

answer 3 : option "b"

answer 4 : option "d"

answer 5 : option "b"

answer 6 : option "a"

answer 7 : option "c"

answer 8 : option "d"

answer 9 : option "c"

answer 10 : option "d"

answer 11 : option "c"

answer 12 option "b"

answer 13 option "c"

answer 14 option "c"

answer 15 option "d"

answer 16 option "a"

answer 17 option "b"

answer 18 option "c"

answer 19 option "a"

answer 20 option "a"

answer 21 option "c"

d