The three sides of a triangle are n, 3n+2, and 5n−6. if the perimeter of the triangle is 41 feet, what is the length of each side?

n+ 3n+2 +5n-6 = 41

9n-4=41

9n=45

n=5

side 1 =5

side 2= 17

side 3 =19

Hope this helps! :)

n + (3n + 2) + (5n - 6) = 41

Combine like terms.

n + 3n + 5n = 9n

Now we're left with 9n + 2 - 6

Combine +2 and -6

2 - 6 = -4

Now, we're left with 9n - 6 = 41

Add 6 to both sides,

9n = 47

Divide both sides by 9

n = 5.2

Now that we know the value of n, we can find the length of each side.

Side 1 = n

Side 1 = 5.2

Side 2 = 3n + 2

Side 2 = 3 * 5.2 + 2

Side 2 = 17.6

Side 3 = 5n - 6

Side 3 = 5 * 5.2 - 6

Side 3 = 20