The sum of two numbers is 21 the second number is 6 times the first number of

the numbers are 3 and 18

let the first number be n then the second number = 6n and the sum

sum = n + 6n = 21 thus

7n = 21

divide both sides of the equation by 7

n = = 3

the numbers are 3 and 6 × 3 = 18 → (3 + 18 = 21)

hello from mrbilldoesmath!

answer:

x - 3

discussion:

x^2 - 9 = (x-3) (x+3)   so

(x^2-9)/ (x + 3) = x-3

you,

mrb

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step-by-step explanation:

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