The equation y=x^3 + 3 is symmetric with respect to which of he following? a. the y-axis b. the line y = x + 3 c. the point (0,3) d. the x-axis

Subtract 3 from both sides,

Let x = X and y - 3 = Y

Then,

So, we have shifted the origin to a point (0, 3).

This is an odd function and the graph of an odd function is symmetrical about the origin.

That is, symmetrical about X = 0, Y = 0

Symmetrical about x = 0,, y - 3 = 0

Symmetrical about x = 0, y = 3.

Hence, the graph is symmetrical about the point (0, 3).

y=mx+b is the final answer!   : )

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step-by-step explanation:

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